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and your total is 583
Will keep trying
But then had to make 8 out of 5,5 and 6. Made 7.
don't think I can get it
594-5-5 = 584
i did this then my boss wanted me to show him how to do an hlookup. quite annoyed! although i do love an hlookup
I was trying to get to 608. I worked out that (75+1) * 8 - 25 = 583. Couldnt make the 8 though.
*shows pad to Gyles Brandreth*
(5+6) x (75-25+4-1)
but a prime factor solution is more elegant, I'm sure you'll agree ;)
25 = 9
574 + 9 = 583
its a squa re, same shape
this is the most badass answer anyone's going to give
It's 100% impossible.
The deviation of 583 from a multiple of 5 will always be of the form
where n is a positive integer, depending on whether it is too big or two large. As the only non-5 numbers to choose from are 6 and 1 we can't form numbers that satisfy (1) and (2) and therefore the question has no real solutions. QED
nonetheless I wonder if Grouchy's answer, intelligently as it is argued, could be affected by the use of indices, as well as divisions of different multiples of 5...obviously anything involving 5n^x will result in 5m, but perhaps x^5n could be combined with y or y^5m, or even (5l/5k)^5j...the numbers being raised to powers would have to share factors. For example, 75/25 is 3; 3^5 is 243 and 6^5 is 7776; the divisor is 32, which when added to 1 becomes 33, which is 5n+3/5n-2...you see, in theory, how 583 could be attained
aye but you can't just throw the rules out can you. you could make the same argument for any arbitrary function which would make the game trivial
bullshit! it's called bidmas for a reason
there's your 3. 5n/5m = n/m = l